Fyzikální otázka
Se ptáš na to, co to emituje nebo na co? Mi v tý druhý části nějak chybí otázka...
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Nechci na tebe bejt ošklivej a ani nejsem fyzik, ale stačilo juknout na wikipedii a tam se dočteš:
"Heat
One gram of 238Pu corresponds to 1/238 moles, which is 2.53×1021 plutonium atoms. Considering its half-life t1/2 = 87.7 years, its activity is
{\displaystyle A=\lambda N={\frac {\ln 2}{t_{1/2}}}N=634\,{\mbox{GBq}}} {\displaystyle A=\lambda N={\frac {\ln 2}{t_{1/2}}}N=634\,{\mbox{GBq}}}.
A is the number of 238Pu decays per second per gram (634 billion). Each of the emitted alpha particles has kinetic energy 5.593 MeV or 8.96×10−13 J which is quickly converted to heat when the particle decelerates in the material. Therefore each gram of 238Pu spontaneously generates 0.568 W of heat."
Zdroj: https://en.wikipedia.org/…lutonium-238#Heat
Ten text je jen copy-paste, doporučuju rozkliknout ten link.
"Heat
One gram of 238Pu corresponds to 1/238 moles, which is 2.53×1021 plutonium atoms. Considering its half-life t1/2 = 87.7 years, its activity is
{\displaystyle A=\lambda N={\frac {\ln 2}{t_{1/2}}}N=634\,{\mbox{GBq}}} {\displaystyle A=\lambda N={\frac {\ln 2}{t_{1/2}}}N=634\,{\mbox{GBq}}}.
A is the number of 238Pu decays per second per gram (634 billion). Each of the emitted alpha particles has kinetic energy 5.593 MeV or 8.96×10−13 J which is quickly converted to heat when the particle decelerates in the material. Therefore each gram of 238Pu spontaneously generates 0.568 W of heat."
Zdroj: https://en.wikipedia.org/…lutonium-238#Heat
Ten text je jen copy-paste, doporučuju rozkliknout ten link.
Mě napadlo, že by se z toho daly dělat baterky pro mobily. :D Nechce někdo mobil na nukleární pohon? :D
Tak energie jedne nasrane castice je 5.5 MeV = 5.5x10E6 * 1.602x10E-19 = 8.81x10E-13 J
Petule uz napsal, kolik castic prumerne (spocteno z polocasu rozpadu s exponencialnim poklesem) vyzari gram za sek***u (636 Gcastic), takze pouze a jenom nasobime dal:
W (1kg) = 8.81x10E-13 * 6.36x10E+11 * 1x10E+3 = 5,6x10E+2 W, to je prumerne 560 W
No .. takova mala rychlovarna konvice :-)
Petule uz napsal, kolik castic prumerne (spocteno z polocasu rozpadu s exponencialnim poklesem) vyzari gram za sek***u (636 Gcastic), takze pouze a jenom nasobime dal:
W (1kg) = 8.81x10E-13 * 6.36x10E+11 * 1x10E+3 = 5,6x10E+2 W, to je prumerne 560 W
No .. takova mala rychlovarna konvice :-)
Kukám not original idea: http://e-svet.e15.cz/…edci-1326040
Otazku tazatel Ziky smazal :-)
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